Math Test

Jan 17, 2015 00:00

Bayes’ Theorem

Pr ⁡ ( A | B ) = Pr ⁡ ( A ) × Pr ⁡ ( B | A ) Pr ⁡ ( B ) = Pr ⁡ ( A ) × Pr ⁡ ( B | A ) Pr ⁡ ( A ) × Pr ⁡ ( B | A ) + Pr ⁡ ( ¬ A ) × Pr ⁡ ( B | ¬ A ) Pr conditional 𝐴 𝐵 Pr 𝐴 Pr conditional 𝐵 𝐴 Pr 𝐵 Pr 𝐴 Pr conditional 𝐵 𝐴 Pr 𝐴 Pr conditional 𝐵 𝐴 Pr 𝐴 Pr conditional 𝐵 𝐴 \Pr(A|B)=\frac{\Pr(A)\times\Pr(B|A)}{\Pr(B)}=\frac{\Pr(A)\times\Pr(B|A)}{\Pr(A% )\times\Pr(B|A)+\Pr(\neg A)\times\Pr(B|\neg A)}

Array

[ λ − a − b − c − d λ − e − f − g − h λ − i ] delimited-[] 𝜆 𝑎 𝑏 𝑐 𝑑 𝜆 𝑒 𝑓 𝑔 ℎ 𝜆 𝑖 \left[\begin{array}[]{ccc}\lambda-a&-b&-c\\ -d&\lambda-e&-f\\ -g&-h&\lambda-i\end{array}\right]

Differential

∬ x ⁢ y 2 ⁢ 𝑑 x ⁢ 𝑑 y = 1 6 ⁢ x 2 ⁢ y 3 , double-integral 𝑥 superscript 𝑦 2 differential-d 𝑥 differential-d 𝑦 1 6 superscript 𝑥 2 superscript 𝑦 3 \iint xy^{2}\,dx\,dy=\frac{1}{6}x^{2}y^{3},

Vector Problem

u = − y x 2 + y 2 , v = x x 2 + y 2 , and w = 0 . formulae-sequence 𝑢 𝑦 superscript 𝑥 2 superscript 𝑦 2 formulae-sequence 𝑣 𝑥 superscript 𝑥 2 superscript 𝑦 2 and 𝑤 0 u=\frac{-y}{x^{2}+y^{2}}\,,\quad v=\frac{x}{x^{2}+y^{2}}\,,\quad\text{and}% \quad w=0\,.

Tagged: Misc